Ohm’s Law: Current through a conductor is directly proportional to the voltage across it, if temperature stays constant.
Cover the unknown in the triangle to reveal the correct rearrangement.
With supply \(V\) and bulb resistance \(R\), compute \(I = \tfrac{V}{R}\).
Choose \(R\) so that a device draws safe current from a given voltage.
Picture a tank pushing water through a pipe: that is how voltage pushes charge.
Current is the water flow rate, while resistance is how narrow the pipe is.
V–I graph: slope = 2 Ω
The graph confirms voltage varies linearly with current for a fixed resistor.
Voltage \(V = 12 \text{ V}\); Resistance \(R = 4 \, \Omega\).
Ohm’s Law gives current: \(I = \frac{V}{R}\).
\(I = \frac{12\text{ V}}{4\,\Omega} = 3 \text{ A}\).
The resistor carries a current of \(3 \text{ A}\).
Always convert to SI units before using \(I = V/R\).
If resistance doubles while voltage remains constant, what happens to the current?
Recall Ohm's law \(I = \frac{V}{R}\).
Right! Doubling resistance halves current because \(I\) varies inversely with \(R\).
Check Ohm's law \(I = \frac{V}{R}\); current decreases when resistance increases.
Voltage equals current times resistance: \(V = I R\).
Acts as the push that drives charges through the circuit.
Measures how fast charge flows; more push gives more current.
Opposes current; higher resistance means lower current for the same voltage.