A parabola is the characteristic U-shaped graph of any quadratic function \(y = ax^{2} + bx + c\) with \(a \neq 0\).
Quick check: Which coefficient guarantees the curve is quadratic?
Graph of \(y = x^{2}\)
The curve \(y = x^{2}\) is the base graph for all quadratic functions.
It opens upward, is symmetric about the y-axis, and its vertex—the lowest point—lies at the origin \((0,0)\).
When \(a < 0\), the parabola opens downward.
The graph is a reflection of the upward curve across the \(x\)-axis.
Its vertex now marks the maximum value of the quadratic.
Start with the general quadratic.
Factor out \(a\) from the \(x\) terms.
Complete the square inside the bracket.
Simplify the constant term.
Set the squared term to zero to get the x-coordinate.
Completing the square reveals the vertex formula \(x = -\frac{b}{2a}\), essential for graphing any quadratic.
Graph of \(y = 2(x-1)^2 + 3\)
Compare the parent curve \(y = x^{2}\) to \(y = 2(x-1)^{2}+3\).
The new coefficients show how far the graph slides and how much it stretches.
For \(y = -3(x + 2)^2 - 4\), which statement is true?
In \(y = a(x - h)^2 + k\), the vertex is \((h,k)\). If \(a<0\), the parabola opens downward.
Great! You identified both the correct vertex and the downward opening.
Recall: \((h,k)\) gives the vertex, and a negative \(a\) means the parabola opens downward.
Recap: sign of \(a\) decides opening—up for \(a>0\), down for \(a<0\).
\(b\) slides the parabola left or right, while \(c\) moves it up or down.
Vertex at \(x = -\frac{b}{2a}\) marks the curve’s peak or valley.
Graph is symmetric about the vertical line through the vertex.
Thank You!
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