Imaginary gas of point particles, no intermolecular forces, perfectly elastic collisions; therefore obeys \(PV=nRT\) at every \(T\) and \(P\).
Assumptions: molecules occupy zero volume, exert no attraction, and collide elastically. Average kinetic energy equals \(\tfrac{3}{2}k_{\rm B}T\); Boltzmann constant \(k_{\rm B}\) links single-molecule energy to temperature.
Molecule rebounds elastically from wall
Gas molecules strike the wall in elastic collisions, reversing their normal velocity.
Each hit changes momentum by \(2 m v_x\) toward the wall.
The cumulative impulse of countless \(2 m v_x\) events per second manifests as steady gas pressure.
One molecule hits the wall; its x-momentum reverses, giving change \(2m v_x\).
Collision rate is \(n A v_x/2\). Multiply by \(\Delta p\) to obtain force on the wall.
Pressure is force per area; still expressed with the x-component only.
Isotropy gives \(\langle v_x^{2}\rangle = \langle v^{2}\rangle/3\), inserting the missing \(1/3\).
The factor \(1/3\) emerges because, in an isotropic gas, momentum and energy split equally among x, y, and z directions.
PV vs P curves for a real gas at three temperatures
An ideal gas shows a flat \( PV \)-vs-\( P \) line; \( PV \) stays constant.
Experimental real-gas curves bend away from that line, marking deviation from ideal behaviour.
Higher temperature pushes molecules apart, so the curve flattens and approaches the ideal line.
Equipartition: each degree of freedom carries \( \tfrac{1}{2} k_B T \) energy.
So absolute temperature fixes microscopic kinetic energy scale.
For the same \(T\), smaller \(m\) gives larger \(v_{\text{avg}}\).
Observed particle speeds back-calculate \(T\) using \( \frac{3}{2} k_B T \).
Lock these in!
Pressure arises from countless molecular hits on walls; momentum change per second equals \(P A\).
For an ideal gas \(PV = nRT\); fix \(n\), any two variables determine the third.
Absolute temperature tracks mean kinetic energy: \(\frac{3}{2}kT = \langle \tfrac{1}{2}mv^{2}\rangle\).
Model fails at high pressure or low temperature where intermolecular forces matter.
At 300 K, which gas has the highest rms speed?
\(v_{\text{rms}} \propto \frac{1}{\sqrt{M}}\)
Yes—lighter atoms zip the fastest!
Check the molar masses; lighter means speedier.