An ellipse is all points in a plane whose distances to two fixed foci add to the same constant.
Quick check: If the constant sum is 10 cm and one focus is 6 cm from point P, how far is P from the other focus? Answer: 4 cm
Red segments: \(PF_1 + PF_2\) stays constant
An ellipse is the set of all points \(P\) for which the sum of distances to two fixed points—the foci \(F_1\) and \(F_2\)—is constant.
Watch point \(P\) move. As \(PF_1\) shortens and \(PF_2\) lengthens, their combined length never changes, so the path naturally traces the curve.
Ellipse with labelled axes and vertices
Two perpendicular axes cross at centre \(O\), defining the key components of the ellipse.
An ellipse is governed by three parameters.
Semi-major \(a\) and semi-minor \(b\) are half the major and minor axes.
Focal distance \(c\) measures the centre-to-focus gap.
Goal: derive the relation linking semi-axes \(a, b\) and focal distance \(c\).
Write \(PF_{1}=\sqrt{(x+c)^{2}+y^{2}}\) and \(PF_{2}=\sqrt{(x-c)^{2}+y^{2}}\).
Set \(PF_{1}+PF_{2}=2a\).
Isolate a radical, square twice, then collect like terms.
\(x\) and \(y\) cancel, leaving \(a^{2}=b^{2}+c^{2}\).
Imagine a right triangle with legs \(b\) and \(c\); its hypotenuse is \(a\).
Horizontal vs Vertical major axis
Both forms satisfy \( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\) with \(a \ge b\).
If \(a^{2}\) sits under \(x^{2}\), the major axis is horizontal; if under \(y^{2}\), it is vertical.
For the ellipse \( \dfrac{x^{2}}{9} + \dfrac{y^{2}}{16} = 1 \), what is the distance between its two foci?
First find \(c\) using \(c^{2}=a^{2}-b^{2}\); the focal distance is \(2c\).
Excellent! You correctly related \(a, b\) and \(c\) and doubled \(c\) to get the focal distance.
Remember: \(a\) is the semi-major axis length 4, \(b\) is 3, so \(c=\sqrt7\) and distance between foci is \(2c\).
Set of points whose distances to two foci add to a constant.
Standard form: \( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \) with \( a > b > 0 \).
Major axis \(2a\), minor axis \(2b\); foci satisfy \( c^{2} = a^{2} - b^{2} \).
Eccentricity \( e = \frac{c}{a} \); always between 0 and 1.
Reflection property: a line from one focus reflects to the other.
Area formula: \( \text{Area} = \pi a b \).
Attempt exercise 10.2 and sketch ellipses with varying \(e\) to solidify concepts.
Thank You!
We hope you found this lesson informative and engaging.