A locus of points in a plane whose sum of distances from two fixed points – the foci – is constant.
Quiz: If the constant sum is 10 cm, where can the foci never be? Apply the triangle inequality.
Geometry sketch: ellipse with two foci \(F_1\) and \(F_2\).
Each blue point \(P\) on the sketch obeys \(PF_1 + PF_2 = 10\,\text{cm}\).
The fixed 10 cm string keeps its ends at the foci while the pointer roams, tracing the ellipse.
Centre at origin; major axis horizontal. Equation links coordinates to squared axis lengths \(a^{2}\) and \(b^{2}\).
Planet paths around the Sun are nearly elliptical.
Elliptical mirrors focus rays between two foci.
Algebraic model of the ellipse in standard form.
Geometry link: distances to foci \(F_{1}(-c,0)\) and \(F_{2}(c,0)\).
Sum property gives major axis length \(2a\); algebra proves \(c^{2}=a^{2}-b^{2}\).
As \(b\) approaches \(a\), the ellipse flattens into a circle and the foci converge to the centre.
Eccentricity \(e=\frac{c}{a}\). For any ellipse \(0\le e<1\).
\(e=0\) gives a circle; \(e\) near 1 yields a stretched ellipse.
Find \(c=\sqrt{a^{2}-b^{2}}\) then \(e=\frac{c}{a}\).
Larger \(e\) signals more flattening.
Which equation is an ellipse centred at the origin with its major axis along the \(y\)-axis?
Look for the plus sign and unequal positive denominators.
Correctโlarger denominator under y^2 means vertical major axis.
Not quite. Remember: ellipse needs both squared terms positive and added.
Ellipses in a nutshell
Sum of distances to two foci stays constant.
\( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \)\, (\(a \ge b\)).
\( c^{2} = a^{2} - b^{2} \) links axes to foci.
\( e = \frac{c}{a} \) quantifies ovalness.
Changing \( a \) & \( b \) reshapes, keeping area \( \pi a b \).
Up next: parametric form & real-world applications.