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[
{
"slide": 1,
"fragments": [
{
"fragment_index": -1,
"text_description": "Second Law of Motion\nForce meets mass—watch acceleration come alive!",
"image_description": ""
}
]
},
{
"slide": 2,
"fragments": [
{
"fragment_index": -1,
"text_description": "Law in Simple Words",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Newton’s Second Law",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Push harder and an object speeds up more. If the object is heavier, it speeds up less with the same push.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Which will speed up more with the same push: a loaded shopping cart or an empty one?",
"image_description": ""
}
]
},
{
"slide": 3,
"fragments": [
{
"fragment_index": -1,
"text_description": "The Equation",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "\\[F = m \\times a\\]",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Variable Definitions",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "F\nForce (N)",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "m\nMass (kg)",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "a\nAcceleration (m/s²)",
"image_description": ""
},
{
"fragment_index": 6,
"text_description": "Know any two variables to find the third.",
"image_description": ""
},
{
"fragment_index": 7,
"text_description": "Applications",
"image_description": ""
},
{
"fragment_index": 8,
"text_description": "Finding Force\nCompute push required to speed up a trolley.",
"image_description": ""
},
{
"fragment_index": 9,
"text_description": "Finding Mass\nEstimate mass when force and acceleration are known.",
"image_description": ""
},
{
"fragment_index": 10,
"text_description": "Finding Acceleration\nPredict how fast a scooter speeds up under a given force.",
"image_description": ""
}
]
},
{
"slide": 4,
"fragments": [
{
"fragment_index": 1,
"text_description": "Cause & Effect\nRelationship examples—see how force or mass changes acceleration.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "1\nDouble the force\nMass same ⇒ acceleration doubles.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "2\nDouble the mass\nForce same ⇒ acceleration halves.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "3\nNo net force\nAcceleration is zero; speed and direction stay same.",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "Remember: \\(a = \\frac{F}{m}\\) — direct with force, inverse with mass.",
"image_description": ""
}
]
},
{
"slide": 5,
"fragments": []
},
{
"slide": 6,
"fragments": [
{
"fragment_index": -1,
"text_description": "Multiple Choice Question\nCorrect!\nGreat job. You applied the second law correctly.\nIncorrect\nCheck the formula \\(a = \\frac{F}{m}\\) and try again.\nconst correctOption = 1; // 0-based index for 3 m/s²\n const answerCards = document.querySelectorAll('.answer-card');\n const submitBtn = document.getElementById('slide-06-k3n9z7-submitBtn');\n const feedbackCorrect = document.getElementById('slide-06-k3n9z7-feedbackCorrect');\n const feedbackIncorrect = document.getElementById('slide-06-k3n9z7-feedbackIncorrect');\n\n let selectedOption = null;\n\n answerCards.forEach((card, index) => {\n card.addEventListener('click', () => {\n answerCards.forEach(c => c.classList.remove('border-blue-500', 'bg-blue-50'));\n card.classList.add('border-blue-500', 'bg-blue-50');\n selectedOption = index;\n });\n });\n\n submitBtn.addEventListener('click', () => {\n if (selectedOption === null) return;\n\n if (selectedOption === correctOption) {\n feedbackCorrect.classList.remove('hidden');\n feedbackIncorrect.classList.add('hidden');\n } else {\n feedbackIncorrect.classList.remove('hidden');\n feedbackCorrect.classList.add('hidden');\n }\n });",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Question\nA 4 kg cart is pushed with 12 N. Using \\(F = m a\\), what is its acceleration?",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "1\n0.3 m/s²",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "2\n3 m/s²",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "3\n48 m/s²",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "4\n16 m/s²",
"image_description": ""
},
{
"fragment_index": 6,
"text_description": "Hint:\nRearrange \\(a = \\frac{F}{m}\\).",
"image_description": ""
},
{
"fragment_index": 7,
"text_description": "Submit Answer",
"image_description": ""
}
]
},
{
"slide": 7,
"fragments": [
{
"fragment_index": -1,
"text_description": "Key Points",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Stronger push, faster change\nMore applied force gives greater acceleration.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Heavier mass, slower change\nA larger mass accelerates less under the same force.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Formula link\nNewton summed it up: \\(F = m \\times a\\).",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Direct & inverse relations\nAcceleration grows with force and shrinks with mass.",
"image_description": ""
}
]
}
]