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[
{
"slide": 1,
"fragments": [
{
"fragment_index": -1,
"text_description": "Second Law of Motion\nMore force, more speed—see the connection.",
"image_description": ""
}
]
},
{
"slide": 2,
"fragments": [
{
"fragment_index": 1,
"text_description": "Key Idea",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Newton’s Second Law",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "An object accelerates more when the net force is larger and less when its mass is bigger.",
"image_description": ""
}
]
},
{
"slide": 3,
"fragments": [
{
"fragment_index": -1,
"text_description": "Shopping Cart Story",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "1\nEmpty Cart\nSmall mass, gentle push—cart accelerates easily.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "2\nLoaded Cart\nBig mass needs stronger push for the same acceleration.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "3\nDouble Push\nTwice the force makes the cart speed up faster.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Pro Tip:\nSecond Law: more force gives more acceleration, but more mass cuts it down.",
"image_description": ""
}
]
},
{
"slide": 4,
"fragments": [
{
"fragment_index": -1,
"text_description": "The Equation\nApplications",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "\\[F = m \\times a\\]",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Variable Definitions\nF\nNet force (Newtons)\nm\nMass (kilograms)\na\nAcceleration (m/s\n2\n)",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Solve for force\nMultiply mass by acceleration to find net force.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Check units\nUse kg for m and m/s² for a so F is in Newtons.",
"image_description": ""
}
]
},
{
"slide": 5,
"fragments": [
{
"fragment_index": -1,
"text_description": "Force vs Acceleration",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Force vs Acceleration graph for a 2 kg cart",
"image_description": "https://asset.sparkl.ac/pb/sparkl-vector-images/img_ncert/D5mnqCuwDnzLWAsUB8gQmvAh4hOeBybfzAmCAMZ6.png"
},
{
"fragment_index": 2,
"text_description": "Straight line means direct proportion\nThe straight line through the origin is a graphical representation of Force (N) against Acceleration (m/s²).\nBecause the line is straight, doubling acceleration doubles force—showing a direct proportion \\(F \\propto a\\).",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Key Points:\nSlope of line = mass = 2 kg.\nLine passes origin, so zero force at zero acceleration.\nAny point confirms \\(F = ma\\).",
"image_description": ""
}
]
},
{
"slide": 6,
"fragments": [
{
"fragment_index": -1,
"text_description": "Quick Check\nconst correctOption = 1;\n const answerCards = document.querySelectorAll('.answer-card');\n const submitBtn = document.getElementById('slide-06-b3k2q7-submit');\n const feedbackCorrect = document.getElementById('feedbackCorrect');\n const feedbackIncorrect = document.getElementById('feedbackIncorrect');\n \n let selectedOption = null;\n \n answerCards.forEach((card, index) => {\n card.addEventListener('click', () => {\n answerCards.forEach(c => c.classList.remove('border-blue-500', 'bg-blue-50'));\n card.classList.add('border-blue-500', 'bg-blue-50');\n selectedOption = index;\n });\n });\n \n submitBtn.addEventListener('click', () => {\n if (selectedOption === null) return;\n \n if (selectedOption === correctOption) {\n feedbackCorrect.classList.remove('hidden');\n feedbackIncorrect.classList.add('hidden');\n } else {\n feedbackIncorrect.classList.remove('hidden');\n feedbackCorrect.classList.add('hidden');\n }\n });",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Question\nA 10 N force acts on a 2 kg box. Find its acceleration.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "1\n2 m/s²",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "2\n5 m/s²",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "3\n10 m/s²",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "4\n20 m/s²",
"image_description": ""
},
{
"fragment_index": 6,
"text_description": "Hint:\nUse \\(a = \\frac{F}{m}\\).",
"image_description": ""
},
{
"fragment_index": 7,
"text_description": "Submit Answer",
"image_description": ""
},
{
"fragment_index": 8,
"text_description": "Correct!\nGreat! \\(a = \\frac{10}{2} = 5\\ \\text{m/s}^2\\).",
"image_description": ""
},
{
"fragment_index": 9,
"text_description": "Incorrect\nRecall \\(a = \\frac{F}{m}\\). Divide 10 N by 2 kg to get 5 m/s².",
"image_description": ""
}
]
},
{
"slide": 7,
"fragments": [
{
"fragment_index": -1,
"text_description": "Lesson Recap",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Acceleration Factors\nChanges with applied force and the object’s mass.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Core Formula\n\\(F = m \\times a\\) links force, mass, and acceleration.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "More Force\nStronger push gives faster acceleration.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "More Mass\nHeavier objects accelerate less under the same force.",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "Daily Examples\nCart pushes, bike rides, and football kicks show the law.",
"image_description": ""
}
]
}
]