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[
{
"slide": 1,
"fragments": [
{
"fragment_index": -1,
"text_description": "Push Experiment",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "1\nSame Push on Two Boards\nShove an empty skateboard and another loaded with books using equal force.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "2\nQuick Check\nWhich board speeds up more—light or heavy? Make your choice to see.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "3\nWhat You Notice\nThe lighter board accelerates faster. Same push, smaller mass means greater acceleration.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Pro Tip:\nEqual force causes different accelerations when masses differ—key idea of Newton’s Second Law.",
"image_description": ""
}
]
},
{
"slide": 2,
"fragments": [
{
"fragment_index": 1,
"text_description": "Key Equation",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "\\[\\vec F = m\\,\\vec a\\]",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Variable Definitions\n\\( \\vec F \\)\nnet force (N)\n\\( m \\)\nmass (kg)\n\\( \\vec a \\)\nacceleration (m·s\\(^{-2}\\))",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Applications\nPushing a Trolley\nHeavier trolley needs more force to gain the same acceleration.\nKicking a Football\nStronger kick gives larger acceleration to the same ball mass.",
"image_description": ""
}
]
},
{
"slide": 3,
"fragments": [
{
"fragment_index": -1,
"text_description": "Momentum Route",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "1\n\\[ p = m v \\]\nMomentum is mass times velocity; here mass \\(m\\) stays constant.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "2\n\\[ \\vec F = \\frac{d\\vec p}{dt} \\]\nNewton's second law: force equals rate of change of momentum.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "3\n\\[ \\frac{d\\vec p}{dt} = m \\frac{d\\vec v}{dt} \\]\nWith constant mass, pull \\(m\\) outside the derivative.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "4\n\\[ \\vec F = m \\frac{d\\vec v}{dt} = m \\vec a \\]\nThus, force equals mass times acceleration—\\( \\vec F = m \\vec a \\).",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "Key Insight:\nFor constant mass, Newton’s momentum form becomes the familiar \\( \\vec F = m \\vec a \\).",
"image_description": ""
}
]
},
{
"slide": 4,
"fragments": [
{
"fragment_index": -1,
"text_description": "Graphical Insight",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Force–Acceleration graph for a 2 kg mass",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Force ∝ Acceleration\nPlotting Force (N) against Acceleration (m/s²) for a 2 kg body gives a straight line through the origin.\nThe line shows that for fixed mass, Force is directly proportional to Acceleration.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Key Points:\nSlope of the line equals mass (2 kg).\nDouble the acceleration → double the force.",
"image_description": ""
}
]
},
{
"slide": 5,
"fragments": []
},
{
"slide": 6,
"fragments": [
{
"fragment_index": -1,
"text_description": "Multiple Choice Question\nCorrect!\nWell done. \\(a = \\frac{12}{3} = 4\\text{ m/s}^2\\).\nIncorrect\nCheck: \\(a = F/m = 12/3 = 4\\text{ m/s}^2\\).\nconst correctOption = 2;\n const answerCards = document.querySelectorAll('.answer-card');\n const submitBtn = document.getElementById('submitBtn');\n const feedbackCorrect = document.getElementById('feedbackCorrect');\n const feedbackIncorrect = document.getElementById('feedbackIncorrect');\n\n let selectedOption = null;\n\n answerCards.forEach((card, index) => {\n card.addEventListener('click', () => {\n answerCards.forEach(c => c.classList.remove('border-blue-500', 'bg-blue-50'));\n card.classList.add('border-blue-500', 'bg-blue-50');\n selectedOption = index;\n });\n });\n\n submitBtn.addEventListener('click', () => {\n if (selectedOption === null) return;\n\n if (selectedOption === correctOption) {\n feedbackCorrect.classList.remove('hidden');\n feedbackIncorrect.classList.add('hidden');\n } else {\n feedbackIncorrect.classList.remove('hidden');\n feedbackCorrect.classList.add('hidden');\n }\n });",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Question\nA net force of 12 N acts on a 3 kg trolley. What is its acceleration?",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "1\n2 m/s\n2",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "2\n3 m/s\n2",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "3\n4 m/s\n2",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "4\n6 m/s\n2",
"image_description": ""
},
{
"fragment_index": 6,
"text_description": "Hint:\nApply Newton’s second law: \\(a = \\frac{F}{m}\\).",
"image_description": ""
},
{
"fragment_index": 7,
"text_description": "Submit Answer",
"image_description": ""
}
]
},
{
"slide": 7,
"fragments": [
{
"fragment_index": -1,
"text_description": "Key Takeaways",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Force drives change\nA body accelerates only when a net external force acts.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "More force, more acceleration\nAcceleration is directly proportional to the applied force.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Heavier mass, slower change\nAcceleration falls as mass rises for the same force.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "One formula ties all\n\\(F = m a\\) unites force, mass, and acceleration—master it.",
"image_description": ""
}
]
}
]