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[
{
"slide": 1,
"fragments": [
{
"fragment_index": -1,
"text_description": "Meet the Free-Body Diagram\nFree-Body Diagram (FBD)\nA free-body diagram isolates an object and shows all external forces. It is the starting map for force problems.\nKey Characteristics:",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Draw the object as a simple dot or box, separate from surroundings.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Attach arrows from the centre; each arrow represents one external force with correct direction.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Label every arrow: weight, normal, tension, friction, push, etc.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Example:\nBlock on table — arrows for weight (down), normal (up), friction (left), applied push (right).",
"image_description": ""
}
]
},
{
"slide": 2,
"fragments": [
{
"fragment_index": -1,
"text_description": "Forces on a Stationary Block\nIdentify each force\nKey Points:",
"image_description": "https://sparkl-vector-images.s3.ap-south-1.amazonaws.com/presentation_images/s3.amazonaws.com/media-p.slid.es/uploads/2780838/images/11539161/10.png"
},
{
"fragment_index": 1,
"text_description": "Weight \\(W\\) acts vertically downward due to gravity.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "The table pushes upward with an equal normal reaction \\(N\\).",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Static friction \\(f\\) lies along the surface, resisting any push.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Weight \\(W = mg\\) downward",
"image_description": ""
},
{
"fragment_index": 5,
"text_description": "Normal reaction \\(N\\) upward",
"image_description": ""
},
{
"fragment_index": 6,
"text_description": "Static friction \\(f\\) along the surface",
"image_description": ""
}
]
},
{
"slide": 3,
"fragments": [
{
"fragment_index": -1,
"text_description": "Label the Forces Yourself\nPractice: Drag each force name to its arrow on the block, then hit “Check Answers” to self-check your labels.\nDraggable Items\nWeight \\(mg\\)\nNormal Reaction \\(N\\)\nApplied Pull \\(F_{\\text{pull}}\\)\nKinetic Friction \\(f_k\\)\nDrop Zones\nArrow 1\nArrow 2\nArrow 3\nArrow 4\nTip:\nStart with weight; it always points straight down from the block.\nCheck Answers\nResults\n// Drag and drop functionality\n const draggableItems = document.querySelectorAll('.draggable-item');\n const dropZones = document.querySelectorAll('.drop-zone');\n const checkAnswersBtn = document.getElementById('checkAnswersBtn');\n const feedbackArea = document.getElementById('feedbackArea');\n const feedbackContent = document.getElementById('feedbackContent');\n \n // Drag and drop event listeners\n draggableItems.forEach(item => {\n item.addEventListener('dragstart', handleDragStart);\n item.addEventListener('dragend', handleDragEnd);\n });\n \n dropZones.forEach(zone => {\n zone.addEventListener('dragover', handleDragOver);\n zone.addEventListener('drop', handleDrop);\n zone.addEventListener('dragenter', handleDragEnter);\n zone.addEventListener('dragleave', handleDragLeave);\n });\n \n function handleDragStart(e) {\n e.target.classList.add('opacity-50');\n e.dataTransfer.setData('text/plain', e.target.dataset.id);\n }\n \n function handleDragEnd(e) {\n e.target.classList.remove('opacity-50');\n }\n \n function handleDragOver(e) {\n e.preventDefault();\n }\n \n function handleDragEnter(e) {\n e.preventDefault();\n e.target.closest('.drop-zone').classList.add('border-green-500', 'bg-green-50');\n }\n \n function handleDragLeave(e) {\n e.target.closest('.drop-zone').classList.remove('border-green-500', 'bg-green-50');\n }\n \n function handleDrop(e) {\n e.preventDefault();\n const dropZone = e.target.closest('.drop-zone');\n dropZone.classList.remove('border-green-500', 'bg-green-50');\n \n const itemId = e.dataTransfer.getData('text/plain');\n const draggedItem = document.querySelector(`[data-id=\"${itemId}\"]`);\n \n if (draggedItem && dropZone) {\n dropZone.appendChild(draggedItem);\n dropZone.querySelector('.text-center').style.display = 'none';\n }\n }\n \n // Check answers functionality\n checkAnswersBtn.addEventListener('click', () => {\n // Implementation for checking answers would go here\n feedbackArea.classList.remove('hidden');\n feedbackContent.innerHTML = '<p class=\"text-green-600\">Answers checked! Review your results above.</p>';\n });",
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}
]
},
{
"slide": 4,
"fragments": [
{
"fragment_index": -1,
"text_description": "Link Forces to Motion\n\\[F_{\\text{net}} = m a\\]\nVariable Definitions\n\\(F_{\\text{net}}\\)\nNet force (N)\n\\(m\\)\nMass (kg)\n\\(a\\)\nAcceleration (m s⁻²)\nApplications",
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},
{
"fragment_index": 1,
"text_description": "Net Force ≠ 0\nWhen forces stop balancing, \\(F_{\\text{net}}\\) appears and the block’s speed starts to change.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "Predict Acceleration\nUse \\(a = F_{\\text{net}}/m\\). Bigger net force or smaller mass means faster acceleration.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Check Units\n1 N applied to 1 kg produces 1 m s⁻², confirming Newton’s Second Law.",
"image_description": ""
}
]
},
{
"slide": 5,
"fragments": [
{
"fragment_index": -1,
"text_description": "Worked Example: Push That Block\nWe push a 2 kg block with 10 N. Kinetic friction is 2 N. Find the acceleration.\nPro Tip:\nAlways subtract opposing friction before using \\(F = ma\\).",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "1\nList the forces\nForward push 10 N, backward kinetic friction 2 N. Choose forward as positive.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "2\nFind net force\n\\(F_{\\text{net}} = 10\\,\\text{N} - 2\\,\\text{N} = 8\\,\\text{N}\\) forward.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "3\nApply \\(F = ma\\)\n\\(a = \\dfrac{F_{\\text{net}}}{m} = \\dfrac{8}{2} = 4\\ \\text{m/s}^2\\) forward.",
"image_description": ""
}
]
},
{
"slide": 6,
"fragments": [
{
"fragment_index": -1,
"text_description": "Quick Check: Did You Get It?\nQuestion\nA 5 kg block has 15 N rightward and 5 N leftward forces. What is its acceleration?\n1\n2 m/s² rightward\n2\n2 m/s² leftward\n3\n3 m/s² rightward\n4\n10 m/s² rightward\nHint:\nFirst find net force, then apply \\(a = F_{\\\\text{net}}/m\\).\nSubmit Answer\nCorrect!\nNet force = 10 N rightward, so \\(a = 10/5 = 2\\;\\\\text{m/s}^2\\) to the right.\nIncorrect\nRemember: subtract opposing forces, then divide by the mass.\nconst correctOption = 0;\n const answerCards = document.querySelectorAll('.answer-card');\n const submitBtn = document.getElementById('submitBtn');\n const feedbackCorrect = document.getElementById('feedbackCorrect');\n const feedbackIncorrect = document.getElementById('feedbackIncorrect');\n \n let selectedOption = null;\n \n answerCards.forEach((card, index) => {\n card.addEventListener('click', () => {\n answerCards.forEach(c => c.classList.remove('border-blue-500', 'bg-blue-50'));\n card.classList.add('border-blue-500', 'bg-blue-50');\n selectedOption = index;\n });\n });\n \n submitBtn.addEventListener('click', () => {\n if (selectedOption === null) return;\n \n if (selectedOption === correctOption) {\n feedbackCorrect.classList.remove('hidden');\n feedbackIncorrect.classList.add('hidden');\n } else {\n feedbackIncorrect.classList.remove('hidden');\n feedbackCorrect.classList.add('hidden');\n }\n });",
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}
]
},
{
"slide": 7,
"fragments": [
{
"fragment_index": -1,
"text_description": "Key Takeaways\nThank You!\nWe hope you found this lesson informative and engaging.",
"image_description": ""
},
{
"fragment_index": 1,
"text_description": "Begin by sketching a clear free-body diagram of the block.",
"image_description": ""
},
{
"fragment_index": 2,
"text_description": "On a level plane, weight \\(mg\\) downward balances normal force \\(N\\) upward.",
"image_description": ""
},
{
"fragment_index": 3,
"text_description": "Static or kinetic friction acts opposite the intended or actual motion.",
"image_description": ""
},
{
"fragment_index": 4,
"text_description": "Net horizontal force \\( \\Sigma F_x = ma \\); its direction sets the block’s acceleration.",
"image_description": ""
}
]
}
]